下面为大家整理的是九道SAT数学练习题的内容，包括了一些常见的知识点。SAT数学题拥有自己的逻辑关系和解题方法，这些都是大家在备考的时候，需要格外注意的部分。下面我们一起来看看这些数学题的详细内容吧。
1.On the last day of a one-week sale, customers numbered 
through 
were waited on. How many customers were waited on that day?
直接获取无忧名师的服务点击进入 >>>>有问题?找免费的无忧专家咨询! 或联系QQ客服： ，也可以通过在线咨询处留言，把您最关心的问题告诉我们。
Answer Choices
(A) 
(B) 
(C) 
(D) 
(E) 
2.For how many positive two-digit integers is the ones digit greater than twice the tens digit?
A. 
B. 
C. 
D. 
E. 
3.If 
is a number from Column 
and 
is a number from Column 
in the table above, how many different values are possible for 
?
A. Nine
B. Eight
C. Seven
D. Six
E. Five
4.If 
is an odd integer, which of the following is an even integer?
A. 
B. 
C. 
D. 
E. 
5.The length of a rectangle is increased by 20%, and the width of the rectangle is increased by 30%. By what percentage will the area of the rectangle be increased?
(A) 25%
(B) 36%
(C) 50%
(D) 56%
(E) 60%
6.If 
and 
, then 
exceeds 
by
A 1/4
B 1/8
C 1/16
D 1/32
E 1/64
7.If 2^a = 4^b, which of the following expresses a in terms of b?
Answer Choices
(A) b over 2
(B) b
(C) 2 times b
(D) 4 times b
(E) 2^b
8.A mechanic can install carburetors in 3 cars every 4 hours. At that rate, how long will it take the mechanic to install carburetors in 5 cars?
(A) 6 hr 20 min
(B) 6 hr 40 min
(C) 7 hr 15 min
(D) 7 hr 30 min
(E) 7 hr 45 min
9.What is the maximum number of nonoverlapping squares with sides of length 3 that will fit inside of a square with sides of length 6?
(A) Two
(B) Three
(C) Four
(D) Six
(E) Nine
Explanation
1.The correct answer is C
The number of customers who were waited on that day is 
, as the total number of customers is those customers numbered 
to 
inclusive.
2.The correct answer is A
The correct answer is (A). If the tens digit is 
, there are 
positive two-digit integers with the ones digit greater than twice the tens digit: 
and 
. If the tens digit is 
, there are 
positive two-digit integers with the ones digit greater than twice the tens digit: 
and 
. If the tens digit is 
, there are 
positive two-digit integers with the ones digit greater than twice the tens digit: 
and 
. If the tens digit is 
, there is 
positive two-digit integer with the ones digit greater than twice the tens digit: 
. If the tens digit is equal to or greater than 
, then the ones digi
3.The correct answer is E
First, add the labeled points 
, 
, 
, 
, 
, and 
to the figure, as shown above. Then segment 
bisects 
, so 
, and 
. Thus, 
. Similarly, 
, because 
and 
are of equal measure and the sum of their measures is 
. From the figure, it follows that 
. Therefore, 
.
4.The correct answer is E
If 
is an odd integer, then 
and 
are odd integers. Similarly, choices 
and 
are odd integers. Since an odd integer subtracted from another odd integer is always an even integer, 
is even.
5.The correct answer is D
Let 
and 
be the original length and width of the rectangle, respectively. If we denote by 
and 
the new length and width of the rectangle, respectively, then we have:
and 
So, the new area will be:
where (
) is the original area of the rectangle.
So the area is increased by 
.
6.The correct answer is E
“
exceeds 
” is interpreted mathematically as the value of 
and is evaluated as follows:
7.The correct answer is D
Choice (C) is correct. Since 4 = 2^2, it follows that 4^b = (2^2)^b = 2^(2 times b). Therefore, 2^a = 4^b = 2^(2 times b), from which it follows that a = 2 times b.
8.The correct answer is B
From the information given, you can write the proportion 3 cars is to 4 hours as 5 cars is to x hours, where x represents the number of hours the mechanic will take to install carburetors in 5 cars. This gives 3 cars over 4 hours = 5 cars over x hours, which simplifies to 3 times x = 4 times 5 = 20. Therefore, x = 20 over 3 = 6 and (2 over 3) hours. Since 2 over 3 hour is 40 minutes, x is 6 hours 40 minutes.
9.The correct answer is C
Choice (C) is correct. A square with sides of length 3 has area 9, and a square with sides of length 6 has area 36. Thus at most 36 ÷ 9 = 4 squares of side length 3 can fit inside a square of side length 6 without overlapping. And in fact, it is possible to fit the four squares of side length 3 inside a square of side length 6 with no overlap; if the four squares with sides of length 3 are arranged in two rows with two squares in each row, they will fit inside of the square with sides of length 6 without overlapping. Therefore, the maximum number of nonoverlapping squares with sides of length 3 that will fit inside of a square with sides of length 6 is four.
以上就是这九道SAT数学练习题及答案的详细内容，后面附有详细的答案解析。大家可以在备考的时候，对此加以适当的练习和应用，测试自己在数学方面知识点的掌握情况。
无忧倾情回馈客户，零利润SAT香港考团，详细信息
更多SAT数学相关：
北京SAT数学培训
SAT数学练习题五例
SAT数学高分备考需摆正心态
SAT数学备考技巧之错题总结
