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SAT数学练习题8道

  下面为大家整理的是8道SAT数学练习题的内容,后面都附有详细的答案解析。SAT数学考试是非常注重对考生实际运用知识点能力的考察的,所以大家在备考的时候,一定要多加练习才行。下面我们来看看详细内容吧。

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  1.A machine can insert letters in envelopes at the rate of 120per minute. Another machine can stamp the envelopes at the rate of 3per second. How many such stamping machines are needed to keep up with 18inserting machines of this kind? 

  Answer Choices

  (A) 12 

  (B) 16 

  (C) 20

   (D) 22 

  (E) 24 

  1.The correct answer is A

  Explanation

  First you can change 1minute to 60seconds so that the ratios are both in envelopes per second. One inserting machine inserts letters at the rate of 120per 60seconds, or 2per second. So 18machines would insert 36letters per second. 

  Let xbe the number of stamping machines needed to keep up with 18inserting machines. Then, since one machine stamps 3envelopes per second, xmachines stamp 3 times xenvelopes per second. You can write the equation 3 times x = 36, which gives x = 12.

 

  2.If 22 times 3 times Q = 6, then Q =

  (A) 1 over 11

  (B) 1 over 10

  (C) 10

  (D) 11

  (E) 20

  2.The correct answer is A

  Explanation

  The question states that 22 times 3 times Q = 6. Solving for Q gives Q = 6 over (22 times 3) = 1 over 11 when the fraction is reduced.

  

math image

 

  3.In the figure, the slope of the line through points P and Q is three over two. What is the value of k?  

  Answer Choices

  (A) 4 

  (B) 5 

  (C) 6

   (D) 7

   (E) 8 

  3.The correct answer is B

  Explanation

  The slope of a line in a coordinate plane is given by the fraction whose numerator is the change in ybetween any two points on the line and whose denominator is the change in xbetween the same points on the line.

   The question asks for the value of k, which is the x-coordinate of point Q.

   The change in ybetween points Pand Qis 7 minus 1 = 6. The change in xbetween these points is k-1. Since the slope is 3 over 2, it follows that 6 over (k minus 1) = 3 over 2. Solving this equation gives (3 times k) minus 3 = 12. Therefore, 3 times k = 15, and k = 5.

 

  4.In the xy-plane, line lis perpendicular to the graph of the function function f of x = (5 times x) minus 2. Line lcould be the graph of which of the following functions?  

  Answer Choices

  (A) function g of x = negative ( 5 times x) 

  (B) function g of x = negative (1 over 5) times x

   (C) function g of x = x minus 2

   (D) function g of x = (1 over 5) times x

  (E) function g of x = 5 times x

  4.The correct answer is B

  Explanation

  If two lines are perpendicular, the product of their slopes is equal to negative 1. The function function f of x = (5 times x ) minus 2is in slope-intercept form, so the slope of the graph of function f of x = (5 times x ) minus 2is equal to 5. Therefore, the slope of line lmust be equal to negative (1 over 5). The only choice that corresponds to a slope of negative (1 over 5)is function g of x = negative (1 over 5 ) times x.

 

  5.If (5 times x) minus 3 = 2 times a, then (5 times x) minus 3 over 2 equals

  Answer Choices

  (A) a over 4 

  (B) a over 2 

  (C) a 

  (D) 2 times a 

  (E) 4 times a 

  5.The correct answer is C

  Explanation

  You are given that (5 times x) minus 3 = 2 times a. Dividing both sides of the equation by 2gives((5 times x) minus 3) over 2 = a. Thus, the answer is a.

 

  6.Ten cars containing a total of 32people passed through a checkpoint. If none of these cars contained more than 4people, what is the greatest possible number of these cars that could have contained exactly 2people? 

  Answer Choices

  (A) One

  (B) Two

  (C) Three

  (D) Four

  (E) Five

  6.The correct answer is D

  Explanation

  It could not be true that each of the ten cars contained exactly 2people, as this would give a total of only 20. If nine of the cars contained exactly 2people, the remaining car could have no more than 4people, for a total of only 22. Continuing in the same way, a pattern develops. If eight of the cars contained exactly 2people, the remaining two cars could have no more than 4people each, for a total of only 24. If seven of the cars contained exactly 2people, the total number of people could be only 26. From the pattern, you can see that if four of the cars contained exactly 2people, and the remaining six cars contained the maximum of 4people, the total number would be 32, as given in the question. Therefore, at most four of the ten cars could have contained exactly2people.

 

  7.If pis an odd integer, which of the following is an even integer?  

  Answer Choices

  (A) p minus 2 

  (B) p^2 

  (C) p^2 minus 2 

  (D) (p minus 2)^2 

  (E) p^2 minus p 

  7.The correct answer is E

  Explanation

  If pis an odd integer, then p minus 2and p^2are odd integers. Similarly, choices Cand Dare odd integers. Since an odd integer subtracted from another odd integer is always an even integer, p^2 minus pis even.

 

  8.IfSis the set of positive integers that are multiples of7, and ifTis the set of positive integers that are multiples of13, how many integers are in the intersection ofSandT?

  Answer Choices

  (A) None

  (B) One

  (C) Seven

  (D) Thirteen

  (E) More than thirteen

  8.The correct answer is E

  Explanation

  The intersection of sets Sand Tis the set of integers that are in Sand also in T. Set Sconsists of all positive integers that are multiples of 7, and set Tconsists of all positive integers that are multiples of 13, so the intersection of Sand Tis the set of positive integers that are multiples of both 7and 13. This is the set of all positive integers that are multiples of 7 times 13 = 91. There are an infinite number of positive integers that are multiples of 91, so there are more than thirteen integers in the intersection of Sand T.

  以上就是这8道SAT数学练习题及答案的详细内容,包括了一些常见的知识点。大家可以在备考的时候,对此加以适当的练习和应用,测试自己在数学方面知识点的掌握情况。

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